跟crakman做sas base认证试题（47）

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                <p><font size="4">47.The following output is created by the FREQUENCY procedure: <br>
<br>
&nbsp;&nbsp;&nbsp;&nbsp;  The FREQ Procedure <br>
<br>
  Table of region by product<br>
<br>
  region&nbsp;&nbsp;&nbsp;&nbsp;  product <br>
<br>
  Frequency|<br>
  Percent  |<br>
  Row Pct  |<br>
  Col Pct  |corn&nbsp;&nbsp;&nbsp;  |cotton  |oranges |  Total<br>
  ---------+--------+--------+--------+<br>
  EAST&nbsp;&nbsp;&nbsp;&nbsp;  |&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  2 |&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  1 |&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  1 |&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  4<br>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  |  22.22 |  11.11 |  11.11 |  44.44<br>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  |  50.00 |  25.00 |  25.00 |<br>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  |  50.00 |  33.33 |  50.00 |<br>
  ---------+--------+--------+--------+<br>
  SOUTH&nbsp;&nbsp;&nbsp;  |&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  2 |&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  2 |&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  1 |&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  5<br>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  |  22.22 |  22.22 |  11.11 |  55.56<br>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  |  40.00 |  40.00 |  20.00 |<br>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  |  50.00 |  66.67 |  50.00 |<br>
  ---------+--------+--------+--------+<br>
  Total&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  4&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  3&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  2&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  9<br>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  44.44&nbsp;&nbsp;&nbsp;  33.33&nbsp;&nbsp;&nbsp;  22.22&nbsp;&nbsp;  100.00<br>
<br>
Which TABLES option(s) would be used to eliminate the<br>
row and column counts and just see the frequencies and percents?</font></p>
<p><font size="4">&nbsp;&nbsp;&nbsp;&nbsp;  A. norowcount nocolcount<br>
&nbsp;&nbsp;&nbsp;&nbsp;  B. freq percent<br>
&nbsp;&nbsp;&nbsp;&nbsp;  C. norow nocol<br>
&nbsp;&nbsp;&nbsp;&nbsp;  D. nocounts</font></p>
<p><font size="4">Answer: C<br>
本题考察的是PROC FREQ过程步中TABLE语句的参数。<br>
答案是NOROW NOCOL。<br>
具体看官方解释：<br>
</font><a href="http://support.sas.com/documentation/cdl/en/procstat/63104/HTML/default/viewer.htm#procstat_freq_sect010.htm"><font size="4"><!-- m --><a class="postlink" href="http://support.sas.com/documentation/cdl/en/procstat/63104/HTML/default/viewer.htm#procstat_freq_sect010.htm">http://support.sas.com/documentation/cd ... ect010.htm</a><!-- m --></font></a></p> <a href="http://hi.baidu.com/crack%5Fman/blog/item/cf0e5839324001fe3c6d9784.html">阅读全文</a>
               
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