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楼主
楼主 |
发表于 2007-5-6 00:27:59
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只看该作者
正交方差分析,F值为零是什么原因啊?
data dx;
input x1 x2 x3 x4 y;
cards;
1 1 1 1 25.28
1 2 2 2 26.95
1 3 3 3 27.64
2 1 2 3 26.01
2 2 3 1 29.04
2 3 1 2 34.67
3 1 3 2 33.6
3 2 1 3 32.17
3 3 2 1 30.33
;
proc anova;
class x1 x2 x3 x4;
model y=x1 x2 x3 x4;
means x1 x2 x3 x4;
run;
SAS 系统 00:17 Tuesday, May 6, 2003 1
The ANOVA Procedure
Class Level Information
Class Levels Values
x1 3 1 2 3
x2 3 1 2 3
x3 3 1 2 3
x4 3 1 2 3
Number of observations 9
SAS 系统 00:17 Tuesday, May 6, 2003 2
The ANOVA Procedure
Dependent Variable: y
Sum of
Source DF Squares Mean Square F Value Pr > F
Model 8 91.51488889 11.43936111 . .
Error 0 0.00000000 .
Corrected Total 8 91.51488889
R-Square Coeff Var Root MSE y Mean
1.000000 . . 29.52111
Source DF Anova SS Mean Square F Value Pr > F
x1 2 44.57108889 22.28554444 . .
x2 2 10.09175556 5.04587778 . .
x3 2 14.46828889 7.23414444 . .
x4 2 22.38375556 11.19187778 . .
SAS 系统 00:17 Tuesday, May 6, 2003 3
The ANOVA Procedure
Level of --------------y--------------
x1 N Mean Std Dev
1 3 26.6233333 1.21343864
2 3 29.9066667 4.39456862
3 3 32.0333333 1.63927830
Level of --------------y--------------
x2 N Mean Std Dev
1 3 28.2966667 4.60730218
2 3 29.3866667 2.62721018
3 3 30.8800000 3.54712560
Level of --------------y--------------
x3 N Mean Std Dev
1 3 30.7066667 4.86302718
2 3 27.7633333 2.27194484
3 3 30.0933333 3.11649376
Level of --------------y--------------
x4 N Mean Std Dev
1 3 28.2166667 2.62374414
2 3 31.7400000 4.18261880
3 3 28.6066667 3.19174456 |
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